SOLUTION: A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be sone in 18 min. How long would it take the second copu machine

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Question 121891This question is from textbook
: A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be sone in 18 min. How long would it take the second copu machine to do the copying alone?
i have:
x=30
x+y=18
that would be -12..not right?
This question is from textbook

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A copy machine can copy a report in 30 mins. When a second copy machine is used at the same time, the copying can be done in 18 min. How long would it take the second copy machine to do the copying alone?
:
Nice try, but let's do it this way.
:
Let x = time required when using both machines.
Let the completed job = 1
:
we know that copy machine 1 will do x/30 of the job
and
copy machine 2 will do x/18 of the job
:
Together:
Machine 1's fraction + Machine 2's fraction = the completed job (1)
x%2F30 + x%2F18 = 1
:
Get rid of those annoying denominators, multiply equation by 30*18 = 540
540*x%2F30 + 540*x%2F18 = 540(1)
:
Cancel out the denominators and you have:
:
18x + 30x = 540
:
48x = 540
x =540%2F48
x = 11.25 minutes or we could say 11 min 15 secs
:
:
Check our solution like this:
11.25/30 + 11.25/18 =
.375 + .625 = 1
:
Did this make sense to you? Enlighten you a little bit?