SOLUTION: Felicia and Rachelle are students in Mr. Johnston's Math 12 class. They got behind on their workcand need to finish seven assignments on the weekend. It would take Felicia 4 hours
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Felicia and Rachelle are students in Mr. Johnston's Math 12 class. They got behind on their workcand need to finish seven assignments on the weekend. It would take Felicia 4 hours
Log On
Question 121862: Felicia and Rachelle are students in Mr. Johnston's Math 12 class. They got behind on their workcand need to finish seven assignments on the weekend. It would take Felicia 4 hours to finish the work by herself. It would take Rachelle 5 hours. If they worked together, how long would it take them to finish the work?
(answer in hours and minutes please:] ) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! t would take Felicia 4 hours to finish the work by herself. It would take Rachelle 5 hours. If they worked together, how long would it take them to finish the work?
(answer in hours and minutes please:] )
:
Let t = time required if they work together:
:
Let the completed work = 1
: + = 1
:
Multiply equation by 20 to get rid of the denominator
20* + 20* = 20(1)
Cancel out the denominators and you have:
:
5t + 4t = 20
9t = 20
t =
t = 2.222 hr
:
Change .222 hrs to minutes: .222 * 60 = 13.3 minutes
2 hrs 13 min working together:
:
:
Check solution using the decimals
2.222/4 + 2.222/5 =
.5555 + .4444 = .9999 ~ 1