SOLUTION: Hi may I have some help with the following word problem.
A jeweler has three small solid spheres made of gold, of radius 2mm, 3mm, and 4mm. He decides to melt these down and m
Algebra ->
Equations
-> SOLUTION: Hi may I have some help with the following word problem.
A jeweler has three small solid spheres made of gold, of radius 2mm, 3mm, and 4mm. He decides to melt these down and m
Log On
Question 121824: Hi may I have some help with the following word problem.
A jeweler has three small solid spheres made of gold, of radius 2mm, 3mm, and 4mm. He decides to melt these down and make just one sphere out of them. What will the radius of this larger sphere be? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! ASSUMING ALL SPHERES ARE THE SAME THICKNESS THEN:
AREA=PIR^2=3.14*2^2=3.14*4=12.56 MM^2
AREA=3.14*3^2=3.14*9=28.26 MM^2
AREA=3.14*4^2=3.14*16=50.24 MM^2
TOTAL AREA=12.56+28.26+50.24=91.06 MM^2
91.06=3.14R^2
R^2=91.06/3.14
R^2=29
R=SQRT29
R=5.385 MM IS THE NEW RADIUS.
(