SOLUTION: How would I solve this system of linear inequalities by graphing: x - y < or = to 3 x + y > or = to 6

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Question 121798: How would I solve this system of linear inequalities by graphing:

x - y < or = to 3 x + y > or = to 6
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X-Y=3 OR -Y=-X+3 OR Y=X-3 (RED LINE).
TO FIND POINTS FOR PLOTTING SET X=0 & SOLVE FOR Y THUS:
Y=0-3
Y=0 THUS YOU HAVE THE POINT (0,-3).
SET Y=0 & SOLVE FOR X THUS:
0=X-3
X=3 THUS YOU HAVE THE POINT (3,0).
X+Y=6 OR Y=-X+6 (GREEN LINE).
HERE WE DO THE SAME.
Y=-0+6
Y=6 THUS YOU HAVE THE POINT (0,6).
0=-X+6
-X=-6
X=6 THUS YOU NAVE (-6,0).
+graph%28+300%2C+200%2C+-6%2C+6%2C+-10%2C+10%2C+y+=+x+-3%2C+y+=+-x+%2B6%29+ (graph 300x200 pixels, x from -6 to 6, y from -10 to 10, of TWO functions y = x -3 and y = -x +6).
SOLUTION (4.5,1.5)