SOLUTION: t-3/2t-4 - 1/12=t+1/3t+6

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Question 121743: t-3/2t-4 - 1/12=t+1/3t+6
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(t-3)/(2t-4) - 1/12 = (t+1)/(3t+6)
Multiply thru by 12(t^2-4) to get:
8(t-3)(t+2) - (t^2-4) = 4(t+1)(t-2)
8(t^2-t-6) - (t^2-4) = 4(t^2-t-2)
3t^2-4t-36 = 0
t = [4 +- sqrt(16-4*3*-36)]/6
t = [4 +- sqrt448]/6
t = 4.1943 or t = -2.861
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cheers,
Stan H.