SOLUTION: A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?

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Question 121625: A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember the circumference of a circle is C=pi%2Ad where d is the diameter of the circle


So let d=diameter of the earth

This means the circumference of the earth is:


C=pi%2Ad


Now since the person is 6 feet tall, this means we're going to add 6 to the diameter to get d%2B6


So the person's head traces out the circumference:

C=pi%2A%28d%2B6%29



Now subtract the second equation from the first equation to get


pi%2Ad-pi%2A%28d%2B6%29



pi%2Ad-pi%2Ad%2B6pi Distribute



cross%28pi%2Ad-pi%2Ad%29%2B6pi Combine like terms



6pi Simplify


So using pi=3.14 we get


6%283.14%29=18.84



So the person's head traveled about 18.84 feet further than the person's feet.




Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?
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If you assume the radius of the earth is x-ft, the
circumference is 2(pi)x ft.
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If you add the 6 ft to the radius you have a radius of x+6 ft.
The circumference of the the path of the head is 2(pi)(x+6) ft.
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The difference is [2pi(x+6)]-[2(pi)x] ft
2(pi)x+12pi - 2(pi)x
= 12(pi) ft or about 37.6991 ft.
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Cheers,
Stan H.