SOLUTION: I can't figure this one out, and you please help me? A train ticket in a certain city is $1.50. People who use the train also have the option of purchasing a frequent rider pass

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I can't figure this one out, and you please help me? A train ticket in a certain city is $1.50. People who use the train also have the option of purchasing a frequent rider pass      Log On


   



Question 121546: I can't figure this one out, and you please help me?
A train ticket in a certain city is $1.50. People who use the train also have the option of purchasing a frequent rider pass for $18.75 each month. With the pass, each ticket costs only $.75. Determine the number of times in a month the train must be used so that the total monthly cost without the pass is the same as the total monthly cost with the pass. Show the equation and solve.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
1.50x=18.75+.75x
1.50x-.75x=18.75
.75x=18.75
x=18.75/.75
x=25 rides is the answer.
1.50*25=18.75+.75*25
37.50=18.75+18.75
37.50=37.50