SOLUTION: Find an equation of the line containing the given pair of points (-3, -9) and (-6, -8). Please show me how you're getting your answer, I keep getting this question wrong. Thank yo

Algebra ->  Linear-equations -> SOLUTION: Find an equation of the line containing the given pair of points (-3, -9) and (-6, -8). Please show me how you're getting your answer, I keep getting this question wrong. Thank yo      Log On


   

Question 121537: Find an equation of the line containing the given pair of points (-3, -9) and (-6, -8). Please show me how you're getting your answer, I keep getting this question wrong. Thank you!!!
Found 2 solutions by Fombitz, algebrapro18:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope using the two points.
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%28-8-%28-9%29%29%2F%28-6-%28-3%29%29
m=%28-8%2B9%29%2F%28-6%2B3%29
m=-1%2F3
The slope-intercept form of a line is
y=mx%2Bb
y=-%281%2F3%29x%2Bb
Use your points to determine b.
Using (-3,-9), you get
y=-%281%2F3%29x%2Bb
-9=-%281%2F3%29%28-3%29%2Bb
-9=1%2Bb
b=-10
y=-%281%2F3%29x-10

Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of the line containing the given pair of points (-3, -9) and (-6, -8)

    first we need to find the slope between the two points and we do that using this formula:


m+=+%28y2-y1%29%2F%28x2-x1%29

now plugging in number into that we get
m+=+%28-8%2B9%29%2F%28-6%2B3%29
m+=+1%2F-3

    so our slope is -1/3. Now we need to find the equation of the line using 1 of two methods.


    Method 1 - Point slop form


      y - y1 = m(x-x1)
      y + 8 = -1/3(x+6)
      y + 8 = -1/3x - 2
      y = -1/3 x - 10

        Method 2


          -8 = -1/3(-6)+b
          -8 = 2 + b
          -10 =

          y = -1/3x - 10