SOLUTION: These data represent the population of a certain city. Year Population (in thousands) 1950 18 1960 23 1970 29 1980 32 1990 38 2000 42 (a

Algebra ->  Absolute-value -> SOLUTION: These data represent the population of a certain city. Year Population (in thousands) 1950 18 1960 23 1970 29 1980 32 1990 38 2000 42 (a      Log On


   

Question 121433: These data represent the population of a certain city.
Year Population (in thousands)
1950 18
1960 23
1970 29
1980 32
1990 38
2000 42

(a) Draw a line graph for the data.
(b) Use the line graph to predict the population in the year 2010
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+b
USING THE POINTS (5,18)(10,42) WE HAVE A SLOPE OF:
(42-18)/(10-5)=24/5=4.8.
NOW USING ONE SET OF POINTS WE FIND THE Y INERCEPT.
18=4.8*5+b
b=18-24
b=-6
NOW WE HAVE THE LINE EQUATION:
Y=4.8X-6
WHEN X=11 THE Y=4.8*11-6 OR Y=46.8
this says that the population in 2010 will be 46.8 thousand.
Y=mX+b
USING THE POINTS (5,18)(10,42) WE HAVE A SLOPE OF:
(42-18)/(10-5)=24/5=4.8.
NOW USING ONE SET OF POINTS WE FIND THE Y INERCEPT.
18=4.8*5+b
b=18-24
b=-6
NOW WE HAVE THE LINE EQUATION:
Y=4.8X-6
WHEN X=11 THE Y=4.8*11-6 OR Y=46.8
this says that the population in 2010 will be 46.8 thousand.
+graph%28+300%2C+200%2C+-6%2C+12%2C+-10%2C+50%2C+y+=+4.8x-6%29+ (graph 300x200 pixels, x from -6 to 12, y from -10 to 50, y = 4.8x -6).