Question 121279This question is from textbook Beginning and Intermediate Algebra
: Hello,
I'm working on some problems for my chemistry II homework and am a little rusty on this type of math. The problem is...
((1.8)(10^-3))/((4.5)(10^-4))^x = ((6.4)(10^-1))/((1.4)(10^-2))
(the entire left side of the equation is raised to the x power, just in case it isnt clear the way its written out)
I solved the problem up to 4^x=45.7, but can't remember how exactly to finish it from there concerning what to type into my calculator or what format to write the problem in to solve it by hand from this point. I'd appreciate any help anyone can offer, thanks!
This question is from textbook Beginning and Intermediate Algebra
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I solved the problem up to 4^x=45.7
If you are correct up this point,
take the log of both sides to get the
"x" out of the exponent:
xlog4 = log(45.7)
x = [log(45.7]/[log(4)]
x = 2.7571
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Cheers,
Stan H.
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