SOLUTION:
If one of two supplementary angles is 16 degrees smaller than three times the other, find the measure of the larger.
cumulative review chapters 1-6 pg 291
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-> SOLUTION:
If one of two supplementary angles is 16 degrees smaller than three times the other, find the measure of the larger.
cumulative review chapters 1-6 pg 291
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You can put this solution on YOUR website! x+3x-16=180
4x=180+16
4x=196
x=196/4
x=49 degrees for the smaller angle.
180-49=131 degrees for the smallest angle.
proof
49+3*49-16=180
49+147-16=180
196-16=180
180=180