SOLUTION: A number is doubled, and then seven is added. When the result is divided by forty, the quotient is two and the remainder is thirty-three. Find the original number.
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Question 121046: A number is doubled, and then seven is added. When the result is divided by forty, the quotient is two and the remainder is thirty-three. Find the original number. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A number is doubled, and then seven is added. When the result is divided by forty, the quotient is two and the remainder is thirty-three. Find the original number.
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Let the original number be "x".
EQUATION:
(2x + 7)/40 = 2 +33/40
2x+7 = 80 + 33
2x = 106
x = 103
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Cheers,
Stan H.