SOLUTION: write an equation of a line that is perpendicular to the line y=3 through the point (-2,6). thanks
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Question 1210427
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write an equation of a line that is perpendicular to the line y=3 through the point (-2,6). thanks
Answer by
josgarithmetic(39800)
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Your given line is y=3. This is same as
. This is horizontal, with slope of 0.
The line asked for would be vertical, so, no slope; so line you are asked for is
, and this line will contain (-2,6).