SOLUTION: find the range of f(sqrt(x)) = x + 1

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Question 1210356: find the range of
f(sqrt(x)) = x + 1
Answer by ikleyn(52772) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the range of
f(sqrt(x)) = x + 1.
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In order for ' f ' in the left side be a function of real argument, sqrt%28x%29 must be defined.

It requires for ' x ' to be a non-negative real number  x >= 0.


So, the domain of the function in the left side is the set  { x >= 0 }.


Then the range is the set of all real numbers  { y >= 1 }.    <<<---=== ANSWER

Solved, with explanations.