SOLUTION: I am working on a Composition of Functions question. I am thrown off because of the use of fractions within the equation (which haven't been in our practice material). The questi

Algebra ->  Functions -> SOLUTION: I am working on a Composition of Functions question. I am thrown off because of the use of fractions within the equation (which haven't been in our practice material). The questi      Log On


   

Question 120992: I am working on a Composition of Functions question. I am thrown off because of the use of fractions within the equation (which haven't been in our practice material). The question that has me stumped follows. (This question comes from an online MAT113 course that I am taking at a local community college. The material comes from Mathematica 6 for Students.)
f(g(x)) f(x)= 1/x and g(x) = x/x-1 For the life of me, I can't compute the equation.
Thank you in advance for taking the time to help with this problem.
Sincerely,
Karen Davison
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
f(g(x)) f(x)= 1/x and g(x) = x/x-1
:
Substitute g(x) for x in the f(x) = 1/x
which means
Substituting (x/x-1) for x in 1/x
:
f(g(x)) = 1%2F%28x%2F%28%28x-1%29%29%29
:
When dividing, invert the dividing fraction and mulitipy
f(g(x)) = 1+%2A+%28%28x-1%29%2Fx%29 = %28x-1%29%2Fx