|
Question 1209864: For each of the following functions, determine if the function is increasing, decreasing, even, odd, and/or invertible on its natural domain. Select all the properties that apply.
f(x) = \frac{x}{\sqrt{x^2 + 1}} + \frac{1}{x^2} - \frac{x}{x^2 - 1}
Answer by CPhill(1987)   (Show Source):
You can put this solution on YOUR website! Let's analyze the function f(x) = x/√(x² + 1) + 1/x² - x/(x² - 1) to determine its properties.
**1. Natural Domain:**
* **√(x² + 1):** x² + 1 is always positive, so the square root is defined for all real numbers.
* **1/x²:** x ≠ 0
* **x/(x² - 1):** x² - 1 ≠ 0 => x ≠ ±1
Therefore, the domain is all real numbers except x = -1, 0, and 1, or (-∞, -1) U (-1, 0) U (0, 1) U (1, ∞).
**2. Even or Odd:**
* **Even:** f(-x) = f(x)
* **Odd:** f(-x) = -f(x)
Let's test f(-x):
f(-x) = -x/√(x² + 1) + 1/x² + x/(x² - 1)
Now, let's see if f(-x) = f(x) or f(-x) = -f(x):
* f(x) = x/√(x² + 1) + 1/x² - x/(x² - 1)
* -f(x) = -x/√(x² + 1) - 1/x² + x/(x² - 1)
Comparing:
* f(-x) ≠ f(x) (Not even)
* f(-x) ≠ -f(x) (Not odd)
Therefore, the function is **neither even nor odd**.
**3. Increasing or Decreasing:**
* To determine if the function is increasing or decreasing, we need to analyze its derivative, f'(x).
f'(x) = d/dx [ x/√(x² + 1) + 1/x² - x/(x² - 1) ]
Let's find the derivatives of each term:
* **d/dx [ x/√(x² + 1) ]:**
* Using the quotient rule: [(√(x² + 1) * 1) - (x * (1/2)(x² + 1)^(-1/2)(2x))] / (x² + 1)
* = (√(x² + 1) - x² / √(x² + 1)) / (x² + 1)
* = (x² + 1 - x²) / (x² + 1)^(3/2) = 1 / (x² + 1)^(3/2)
* **d/dx [ 1/x² ]:**
* -2/x³
* **d/dx [ -x/(x² - 1) ]:**
* -[(x² - 1) * 1 - x * 2x] / (x² - 1)²
* -[x² - 1 - 2x²] / (x² - 1)²
* -[-x² - 1] / (x² - 1)² = (x² + 1) / (x² - 1)²
Therefore,
f'(x) = 1 / (x² + 1)^(3/2) - 2/x³ + (x² + 1) / (x² - 1)²
Analyzing f'(x) is complex. Due to the various terms and the domain, it's difficult to make a general statement about increasing or decreasing behavior across the entire domain. A graphing calculator or more in-depth calculus analysis would be needed.
**4. Invertibility:**
* Due to the function not being strictly increasing or decreasing across its entire domain, and the breaks in the domain, it is likely **not invertible**.
**Conclusion:**
* **Domain:** (-∞, -1) U (-1, 0) U (0, 1) U (1, ∞)
* **Neither even nor odd**
* **Invertible:** No (likely)
* **Increasing/Decreasing:** Difficult to determine without further analysis (graphing is recommended).
|
|
|
| |
