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Question 120975: 2x+y+z = 5
x+3z = 14
-2x-3y+2z = 2
Answer by madhan_math(34)   (Show Source):
You can put this solution on YOUR website! Given equations are
2x+y+z = 5 ------(1)
x+3z = 14--------(2)
-2x-3y+2z = 2----(3)
First we solve equations (1) and (3),
eqn.(1)*3+eqn.(3)we get,(since cancelling of y)
4x+5x=17--------(4)
Now we solve equations (4) and (2)
eqn.(4)-eqn.(2)*4 (Since cancelling of x), we get,
z=39/7 and substitute this value in equation (2) then we get x=-19/7.
Finally we substitute the x and z values in equation (1) we get
y=34/7.
Therefore, the values are
x=-19/7,
y= 34/7
z= 39/7 (If you like check these values are correct substitute these values in any equation and verify)
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