SOLUTION: Find the quotient and remainder when p(x) is divided by q(x)$, where p(x) = x^4 - x^2 + 3x - 7 and q(x) = x^2 + 2x

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Question 1209675: Find the quotient and remainder when p(x) is divided by q(x)$, where p(x) = x^4 - x^2 + 3x - 7 and q(x) = x^2 + 2x - 5.
Found 2 solutions by CPhill, josgarithmetic:
Answer by CPhill(1987) (Show Source):
You can put this solution on YOUR website!
Here's how to perform polynomial long division to find the quotient and remainder:
```
x^2 - 2x + 8
------------------
x^2 + 2x - 5 | x^4 + 0x^3 - x^2 + 3x - 7
x^4 + 2x^3 - 5x^2
------------------
-2x^3 + 4x^2 + 3x
-2x^3 - 4x^2 + 10x
------------------
8x^2 - 7x - 7
8x^2 + 16x - 40
------------------
-23x + 33
```
Therefore:
* **Quotient:** x² - 2x + 8
* **Remainder:** -23x + 33

Answer by josgarithmetic(39625) (Show Source):
You can put this solution on YOUR website!

x^2 -2x 8 ______________________________________________ x^2+2x-5 | x^4 0x^3 -x^2 +3x -7 x^4 2x^3 -5x^2 ------------------------- 0 -2x^3 4x^2 3x -2x^2 -4x^2 10x ---------------------- 0 8x^2 -7x -7 8x^2 16x -40 ------------------ 0 -23x + 33

p/q is .

SOLUTION: Find the quotient and remainder when p(x) is divided by q(x)$, where p(x) = x^4 - x^2 + 3x - 7 and q(x) = x^2 + 2x - 5.