The graph of f(x) is in red below.
Let's look at the related graph in green, g(x), which
equals what's under the square root radical:
As we see, f(x) stops when it gets to the leftmost x-intercept of g(x)
and begins again at the rightmost x-intercept of of g(x).
The domain of f(x) INCLUDES both x-intercepts of g(x)
So we find the two x-intercepts of
which doesn't factor (which shows that the problem-maker is stupid)
So we stop and turn our attention away from what we're doing while we go
over to the quadratic formula and solve it, and hope we can remember what
we were doing before the stupid problem-maker made us stop and do that.
So the domain of f(x) is
We use " ] " and " [ " to show that the domain INCLUDES those values.
Edwin