Question 1209451: A 1952 hurricane dumped 73.62 inches of rain in 24 hours. Calculate amount (tons) of water on an acre.
73.62 in. = 6.135 ft.
Acre = 43,560 sq. ft.
Gal. of water weighs 8.34 lbs.
Not sure how to solve.
Found 3 solutions by josgarithmetic, timofer, ikleyn:
Answer by josgarithmetic(39621)   (Show Source):
Answer by timofer(105) (Show Source):
Answer by ikleyn(52817)  (Show Source):
You can put this solution on YOUR website! .
First, we should calculate the volume of water.
The volume is the product of the base area (43,560 sq. ft) by the height
(= the depth) of water, which is 6.135 ft in this problem.
So, the volume of water is 43560*6.135 = 267240.6 ft^3.
Next, we should calculate how much gallons is it.
From the conversion table, 1 ft^3 = 7.48052 gallons.
So, 267240.6 ft^3 of water is equivalent to 267240.6*7.48052 = 1999098.653112 gallons of water.
One gallon of water weights 8.74 lbs.
So, 1999098.653112 gallons of water weight 1999098.6531120*8.74 = 17472122.2282 lbs.
To convert it to tons, we should divide the number of lbs by 2000.
S, we do it, and we obtain  = 8736.061 tons of water.
Finally, we round to closest ton, and get the
ANSWER. This amount of water is about 8736 tons.
Solved.
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This problem is super-simple, and a bit of common sense is enough to solve it to the end.
To better understand this amount of water, imagine a train of 50 cisterns of 20 tons of water in each.
One such train carries 50*20 = 1000 tons of water. The length of such a train is about one kilometer.
So, 8736 tons of water is about 9 (nine) such trains.
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