SOLUTION: Solve the inequality x(x + 6) > 16 - x^2 + 14x. Write your answer in interval notation.

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Question 1209290: Solve the inequality x(x + 6) > 16 - x^2 + 14x. Write your answer in interval notation.
Found 2 solutions by mccravyedwin, math_tutor2020:
Answer by mccravyedwin(408) About Me  (Show Source):
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Consider the equation x%2A%28x%2B6%29+=+16+-+x%5E2+%2B+14x

Let's get everything to one side.
x%2A%28x%2B6%29+=+16+-+x%5E2+%2B+14x
x%5E2%2B6x+=+16+-+x%5E2+%2B+14x
x%5E2%2B6x+-+16+%2B+x%5E2+-+14x+=+0
2x%5E2+-+8x+-+16+=+0
2%28x%5E2+-+4x+-+8%29+=+0
x%5E2+-+4x+-+8+=+0

That last equation is of the format ax%5E2%2Bbx%2Bc+=+0
where,
a = 1, b = -4, c = -8
Plug those into the quadratic formula.
x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F%282a%29

x+=+%28-%28-4%29+%2B-+sqrt%28%28-4%29%5E2+-+4%281%29%28-8%29%29%29%2F%282%281%29%29

x+=+%284+%2B-+sqrt%2816%2B32%29%29%2F%282%281%29%29

x+=+%284+%2B-+sqrt%2848%29%29%2F%282%29

x+=+%284+%2B-+sqrt%2816%2A3%29%29%2F%282%29

x+=+%284+%2B-+sqrt%2816%29%2Asqrt%283%29%29%2F%282%29

x+=+%284+%2B-+4%2Asqrt%283%29%29%2F%282%29

x+=+%282%282+%2B-+2%2Asqrt%283%29%29%29%2F%282%29

x+=+2+%2B-+2%2Asqrt%283%29

x+=+2+%2B+2%2Asqrt%283%29 or x+=+2+-+2%2Asqrt%283%29

x+=+5.464 or x+=+-1.464 both of which are approximate.

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Draw a number line with regions A, B, C
region A = stuff to the left of -1.464
region B = stuff between -1.464 and 5.464
region C = stuff to the right of 5.464

Possible test values for regions A,B,C could be: x = -2, x = 0, x = 6 in that order
You plug each test value back into the original inequality x%2A%28x%2B6%29+%3E+16+-+x%5E2+%2B+14x to see if we get a true statement or not.

If we tried x = -2, then,
x%2A%28x%2B6%29+%3E+16+-+x%5E2+%2B+14x
-2%2A%28-2%2B6%29+%3E+16+-+%28-2%29%5E2+%2B+14%2A%28-2%29
-8+%3E+-16
which is true.
Any x value in region A is in the solution set for x%2A%28x%2B6%29+%3E+16+-+x%5E2+%2B+14x

Region A is x+%3C+2+-+2%2Asqrt%283%29 aka -infinity+%3C+x+%3C+2+-+2%2Asqrt%283%29
Yielding the interval notation %28matrix%281%2C3%2C-infinity%2C%22%2C%22%2C2-2sqrt%283%29%29%29
Use curved parenthesis to indicate we do not include the endpoints in the solution set.

If we tried x = 0 then
x%2A%28x%2B6%29+%3E+16+-+x%5E2+%2B+14x
0%2A%280%2B6%29+%3E+16+-+0%5E2+%2B+14%2A0
0+%3E+16
which is false.
Any x value in region B, ie the region between x+=+2+-+2%2Asqrt%283%29+=+-1.464 and x+=+2+%2B+2%2Asqrt%283%29+=+5.464 will make the original inequality false.


The last region to test is region C.
Let's plug in x = 6
x%2A%28x%2B6%29+%3E+16+-+x%5E2+%2B+14x
6%2A%286%2B6%29+%3E+16+-+6%5E2+%2B+14%2A6
72+%3E+64
which is true
Therefore x+%3E+2+%2B+2%2Asqrt%283%29 aka 2+%2B+2%2Asqrt%283%29+%3C+x+%3C+infinity translates to the interval notation %28matrix%281%2C3%2C2+%2B+2sqrt%283%29%2C%22%2C%22%2C+infinity%29%29


We found these two interval notation regions
%28matrix%281%2C3%2C-infinity%2C%22%2C%22%2C2-2sqrt%283%29%29%29 or %28matrix%281%2C3%2C2+%2B+2sqrt%283%29%2C%22%2C%22%2C+infinity%29%29

Glue them together with a set union symbol to end up with this final answer

You can use a graphing calculator like Desmos and GeoGebra to confirm.