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What is the greatest power of 11 that divides into 2894!, with no remainder?
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From 1 to 2894, there are [ 2894/11 ] = 263 integer numbers divisible by 11.
They create / (contribute to) the divisor .
From 1 to 2894, there are [ 2894/11^2 ] = 23 integer numbers divisible by .
They contribute to the additional divisor .
From 1 to 2894, there are [ 2894/11^3 ] = 2 integer numbers divisible by .
They contribute to the additional divisor .
So, the greatest power of 11 that divides 2894! with no remainder is 263 + 23 + 2 = 288. ANSWER
