SOLUTION: How do you factor 4x^2+6xy+9y^2? Could you please help me?

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Question 120912:
How do you factor 4x^2+6xy+9y^2? Could you please help me?
Found 2 solutions by scott8148, checkley71:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
sorry, this expression is NOT factorable

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2+6xy+9y^2
using the quadratic equation:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ we get:
x=(-6+-sqrt[6^2-4*4*9])/2*4
x=(-6+-sqrt[36-144])/8
x=(-6+-sqrt-108])/8
x=(-6+-10.39i)/8
x=(-6+10.39i)/8
x=-6/8+1.299i
x=-.75+-1.299i answers.