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In how many ways can 6 people be arranged to sit around a circular table with 10 chairs?
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Working with circular placing/arrangements, we can think that the chairs are numbered from 1 to 10 inclusive, 
and that the chair number 1 is vacant and is placed in position "North" or {12 o'clock".
Then we have 9 chairs from 2 to 10 to place there 6 people.
    1st person can be placed to any of 9 chairs            (9 options);
    2nd person can be placed to any of 8 remaining chairs  (8 options);
    3rd person can be placed to any of 7 remaining chairs  (7 options);
    4th person can be placed to any of 6 remaining chairs  (6 options);
    5th person can be placed to any of 5 remaining chairs  (5 options);
    6th person can be placed to any of 4 remaining chairs  (4 options).
Thus the total number of different placements/arrangements is this product
    9*8*7*6*5*4 = 60480.    ANSWER
It is the product of 6 consecutive integers in decreasing order, starting from 9.
Solved and explained.
It can be solved/presented/explained in several different ways.
I chose this way since it explains everything from "first principles".