SOLUTION: Solve for $x$: \frac{3x+12}{x+4} = \frac{4x^2 + 8x + 18x^2}{2x^2}.
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Question 1209048
:
Solve for $x$:
\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 18x^2}{2x^2}.
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