SOLUTION: Solve for x. 2sinx + 2tanx = 0

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Question 1208912: Solve for x.

2sinx + 2tanx = 0

Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
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Solve for x.
2sinx + 2tanx = 0
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You want to solve

    2sin(x) + 2tan(x) = 0.


The domain of this equation are all real numbers except of  x = pi%2F2%2Bk%2Api,  where cos(x) = 0.


Rewrite in the form

    2sin(x) + 2%2A%28sin%28x%29%2Fcos%28x%29%29 = 0.


In the domain, multiply both sides by  cos%28x%29%2F2.


Since  cos(x) =/= 0,  you will get an equivalent equation

    sin(x)*cos(x) + sin(x) = 0.


Factor

    sin(x)*(cos(x) + 1) = 0.


So, either sin(x) = 0,  giving the solutions  x = k%2Api,  k = 0, +/-1, +/-2, . . .          (1)

    or  cos(x) + 1 = 0,  cos(x) = -1,  giving  x = pi+%2B+2k%2Api,  k = 0, +/-1, +/-2, . . .    (2)



The set (2) is part of set (1) - so, the general solution to the given equation is the set

    x = k%2Api,  k = 0, +/-1, +/-2, . . .


ANSWER.  The general solution to the given equation is the set  x = k%2Api,  k = 0, +/-1, +/-2, . . .

Solved.