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Solve for x.
2sinx + 2tanx = 0
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You want to solve
    2sin(x) + 2tan(x) = 0.
The domain of this equation are all real numbers except of  x =  ,  where cos(x) = 0.
Rewrite in the form
    2sin(x) +
,  where cos(x) = 0.
Rewrite in the form
    2sin(x) +  = 0.
In the domain, multiply both sides by
 = 0.
In the domain, multiply both sides by   .
Since  cos(x) =/= 0,  you will get an equivalent equation
    sin(x)*cos(x) + sin(x) = 0.
Factor
    sin(x)*(cos(x) + 1) = 0.
So, either sin(x) = 0,  giving the solutions  x =
.
Since  cos(x) =/= 0,  you will get an equivalent equation
    sin(x)*cos(x) + sin(x) = 0.
Factor
    sin(x)*(cos(x) + 1) = 0.
So, either sin(x) = 0,  giving the solutions  x =  ,  k = 0, +/-1, +/-2, . . .          (1)
    or  cos(x) + 1 = 0,  cos(x) = -1,  giving  x =
,  k = 0, +/-1, +/-2, . . .          (1)
    or  cos(x) + 1 = 0,  cos(x) = -1,  giving  x =  ,  k = 0, +/-1, +/-2, . . .    (2)
The set (2) is part of set (1) - so, the general solution to the given equation is the set
    x =
,  k = 0, +/-1, +/-2, . . .    (2)
The set (2) is part of set (1) - so, the general solution to the given equation is the set
    x =  ,  k = 0, +/-1, +/-2, . . .
ANSWER.  The general solution to the given equation is the set  x =
,  k = 0, +/-1, +/-2, . . .
ANSWER.  The general solution to the given equation is the set  x =  ,  k = 0, +/-1, +/-2, . . .
,  k = 0, +/-1, +/-2, . . .
Solved.