SOLUTION: Cannon wants to put as much as he can into an account as soon as he starts working He deposits 25000 at the end of each year for 5 years in an account paying 6% compounded annuall

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Question 1208885: Cannon wants to put as much as he can into an account as soon as he starts working
He deposits 25000 at the end of each year for 5 years in an account paying 6% compounded annually. How much will he have at the end of the 6th year.

Found 2 solutions by KMST, ikleyn:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
At the end of each year, Cannon gets 6% added to the balance.
If the balance at the beginning of a year is b, the interest earned is b%2A6%2F100=b%2A0.06.
That makes the end of the year balance b%2A0.06%2Bb=%280.06%2B1%29b=1.06b .
As that multiplying times 1.06 happens at the end of each year,
at the end of the 6th year the initial 25000 deposit has grown to
25000%2A1.06%5E5=25000%2A1.3382255776=33455.64(rounded to the nearest cent).
The second deposit would have grown to 25000%2A1.06%5E4
The third deposit would have grown to 25000%2A1.06%5E3
The fourth deposit would have grown to 25000%2A1.06%5E2
The fifth deposit would have grown to 25000%2A1.06
The total at the end of the sixth year will be

Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.

Notice that during first 5 years, this saving plan works as a  standard Ordinary Annuity,
and you can calculate its future value after 5 years using standard formula


    FV(in 5 years) = 25000%2A%28%28%281%2B0.06%29%5E5-1%29%2F0.06%29 = 140927.324.


In the 6th year, there is no deposit/withdrawal, so this amount grows in the 6th year
as an one-time deposit with the growth coefficient 1.06.


It gives the final amount after 6 years as

    140927.324*1.06 = 149382.96.


So, the ANSWER is the same as in the post by @KMST.