Question 120878:
which of the ordered pairs are solutions for x+3y=10
(7,1),(10,0),(1,-3),(-8,6)
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
Let's test the first solution (7,1):
 Plug in  and 
 Simplify. Since the two sides of the equation are equal, this means (7,1) is a solution to
-------Now lets test another solution-------
Let's test the second solution (10,0):
 Plug in  and 
Simplify. Since the two sides of the equation are equal, this means (10,0) is a solution to
-------Now lets test another solution-------
Let's test the third solution (1,-3):
 Plug in  and 
 Simplify. Since the two sides of the equation are not equal, this means (1,-3) is not a solution to
-------Now lets test another solution-------
Let's test the fourth solution (-8,6):
 Plug in  and 
Simplify. Since the two sides of the equation are equal, this means (-8,6) is a solution to
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Answer:
So the following ordered pairs are solutions to
(7,1), (10,0), and (-8,6)
Now let's graph the equation and plot the points (7,1), (10,0), (1,-3), and (-8,6)
Here we can see that the points (7,1), (10,0), and (-8,6) lie on the line (they are the green points). These are the solutions to the equation .
Notice that the solution (1,-3) is a point that does not lie on the line since it does not satisfy the equation
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! (7,1) & (10,0)
PROOF
7+3*1=10
7+3=10
10=10
10+3*0=10
10=10
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1+3-3=10
1-9=10
-8(NOT)=10
-8+3*-6=10
-8-18=10
-26(NOT)=10
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