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Z1*Z2 = (a + bi)*(c + di) = ac + bci + adi + bi*di = ac + bci + adi + bd*i^2 = 
      = ac + (bc + ad)i - bd = (ac - bd) + (bc + ad)i.    ANSWER
On the way, I used  i^2 = -1.
Real      part of  Z1*Z2  is  ac - bd.
Imaginary part of  Z1*Z2  is  bc + ad.
Solved.