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Z1*Z2 = (a + bi)*(c + di) = ac + bci + adi + bi*di = ac + bci + adi + bd*i^2 =
= ac + (bc + ad)i - bd = (ac - bd) + (bc + ad)i. ANSWER
On the way, I used i^2 = -1.
Real part of Z1*Z2 is ac - bd.
Imaginary part of Z1*Z2 is bc + ad.
Solved.