SOLUTION: A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance s (in feet) of the ball from the ground afte

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Question 1208730: A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance s (in feet) of the ball from the ground after t seconds is given by
s = 96 + 80t - 16t^2.
A. After how many seconds does the ball strike the ground?
My setup:
0 = 96 + 80t - 16t^2
You say?
B. After how many seconds will the ball pass the top of the building on its way down?
For part B, I must let s = 96 and solve for t. The building is 96 feet tall.
You say?
Answer by ikleyn(52795) About Me  (Show Source):
You can put this solution on YOUR website!
.

Yes, you must solve it.