Let me see.
x^2 + (2\3)x = 1/3
[(2/3) ÷ 2]^2 = 1/9
x^2 + (2/3)x + 1/9 = 1/3 + 1/9
x^2 + (2/3)x + 1/9 = 4/9
(x + 1/3) (x + 1/3) = 4/9
(x + 1/3)^2 = 4/9
Taking the square square on both sides, I get
x + 1/3 = 2/3 & x + 1/3 = -2/3
Now solve for x by setting x + 1/3 to equal 2/3 and then -2/3.
x + 1/3 = 2/3
x = 2/3 - 1/3
x = 1/3
And
x + 1/3 = -2/3
x = -2/3 - 1/3
x = -3/3
x = -1
You say? Found 2 solutions by timofer, MathTherapy:Answer by timofer(105) (Show Source):
Solve by completing the square.
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Let me see.
x^2 + (2\3)x = 1/3
[(2/3) ÷ 2]^2 = 1/9
x^2 + (2/3)x + 1/9 = 1/3 + 1/9
x^2 + (2/3)x + 1/9 = 4/9
(x + 1/3) (x + 1/3) = 4/9
(x + 1/3)^2 = 4/9
Taking the square square on both sides, I get
x + 1/3 = 2/3 & x + 1/3 = -2/3
Now solve for x by setting x + 1/3 to equal 2/3 and then -2/3.
x + 1/3 = 2/3
x = 2/3 - 1/3
x = 1/3
And
x + 1/3 = -2/3
x = -2/3 - 1/3
x = -3/3
x = -1
You say?
x^2 + (2\3)x = 1/3 ====>
====> [(2/3) ÷ 2]^2 = 1/9 <==== CORRECT
x^2 + (2/3)x + 1/9 = 1/3 + 1/9 <===== CORRECT
x^2 + (2/3)x + 1/9 = 4/9 <===== CORRECT
(x + 1/3)(x + 1/3) = 4/9 <==== CORRECT, but in MY OPINION, not necessary
(x + 1/3)^2 = 4/9 <==== CORRECT
Taking the square square on both sides, I get
x + 1/3 = 2/3 & x + 1/3 = -2/3 <====== CORRECT
Now solve for x by setting x + 1/3 to equal 2/3 and then -2/3.
x + 1/3 = 2/3
x = 2/3 - 1/3
x = 1/3 <===== CORRECT
And
x + 1/3 = -2/3
x = -2/3 - 1/3
x = -3/3
x = -1 <====== CORRECT
You say? Well done!!