SOLUTION: The length of a rectangle is eight more than twice it's width. The perimeter is 88 feet. Find the dimensions of the rectangle.

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Question 1208673: The length of a rectangle is eight more than twice it's width. The perimeter is 88 feet. Find the dimensions of the rectangle.
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
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The length of a rectangle is eight  highlight%28highlight%28feet%29%29  more than twice  it's  highlight%28highlight%28its%29%29  width.
The perimeter is 88 feet. Find the dimensions of the rectangle.
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        Pay attention on how I edited your post to make grammar, syntax, wording and meaning correct. 


Let the width be w feet.

Then the length is 2w+8 feet.


    Length + width = 88/2

    Length + width = 44

    (2w+8) + w = 44

    3w + 8 = 44

    3w = 44 - 8 = 36

     w = 36/3 = 12.


ANSWER.  The width is 12 feet;  the length is 2w+8 = 2*12+8 = 32 feet.


CHECK.  Length + width = 32 + 12 = 44 feet, one half of 88 feet, the perimeter.    ! correct !

Solved.