SOLUTION: The equation of a line that is perpendicular to y=-8x-63 and passes through (-5,6)

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Question 1208659: The equation of a line that is perpendicular to y=-8x-63 and passes through (-5,6)
Found 2 solutions by math_tutor2020, josgarithmetic:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

The given equation is of the form y = mx+b
m = -8 = slope

Think of -8 as -8/1
Flip the fraction and flip the sign.
In other words, apply the negative reciprocal.
-8/1 becomes 1/8 which is the perpendicular slope.
Any pair of perpendicular lines will have their slopes multiply to -1, as long as neither line is vertical nor horizontal.


Let's apply point-slope form.
y-y%5B1%5D+=+m%28x+-+x%5B1%5D%29
y-y%5B1%5D+=+expr%281%2F8%29%28x+-+x%5B1%5D%29 Plug in the perpendicular slope
y-6+=+expr%281%2F8%29%28x+-+%28-5%29%29 Plug in the coordinates of the point (-5,6)
y-6+=+expr%281%2F8%29%28x+%2B+5%29
y-6+=+expr%281%2F8%29x+%2B+5%2F8
y+=+expr%281%2F8%29x+%2B+5%2F8%2B6
y+=+expr%281%2F8%29x+%2B+5%2F8%2B48%2F8
y+=+expr%281%2F8%29x+%2B+%285%2B48%29%2F8
y+=+expr%281%2F8%29x+%2B+53%2F8 This is the answer in slope intercept form (y=mx+b)


If you need the answer in standard form (Ax+By=C), then,
y+=+expr%281%2F8%29x+%2B+53%2F8
8y+=+8%28expr%281%2F8%29x+%2B+53%2F8%29
8y+=+x%2B53
8y-x+=+53
-x%2B8y+=+53
-1%28-x%2B8y%29+=+-1%2A53
x-8y+=+-53

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular to y=-8x-63 and contains (-5,6)


slope will be 1%2F8.

y=x%2F8%2Bb

The point to be included:
6=-5%2F8%2Bb
b=6%2B5%2F8
b=6%265%2F8

Equation: y=x%2F8%2B6%265%2F8
(or adjust for another form)