SOLUTION: Evaluate the expression and write the result in the form a + bi. 1/8+10i - 1/8+10i = _____ + _______i I do not know how to divide complex numbers. Note that that 8+10i is

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Evaluate the expression and write the result in the form a + bi. 1/8+10i - 1/8+10i = _____ + _______i I do not know how to divide complex numbers. Note that that 8+10i is       Log On


   



Question 120862This question is from textbook College Algebra
: Evaluate the expression and write the result in the form a + bi.
1/8+10i - 1/8+10i = _____ + _______i
I do not know how to divide complex numbers. Note that that 8+10i is the numerator in both equations.
I would greatly appreciate your help!! Thank you so much.
This question is from textbook College Algebra

Found 2 solutions by checkley71, solver91311:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
I'LL ASSUME YOU MEAN THE (8+10i) IS IN THE DENOMINATOR!!!!!
1/(8+10i)-1/(8+10i)
(8+10i)-(8+10i)/(8+10i)(8+10i)
8-8+10i-10i/(8+10i)(8+10i)
0+0/(8+10i)(8+10i)=0 ANSWER.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I'm pretty sure you meant to say 8 + 10i is the denominator of both fractions, and your problem actually looks like:

%281%2F%288%2B10i%29%29-%281%2F%288%2B10i%29%29

Just like working with any other fractions, if the denominators are equal, then you simply add the numerators.

%281-1%29%2F%288%2B10i%29=0

We could have made this a little more complicated by using a process called rationalizing the denominators, but the result will still be the same. Watch closely.

First thing is to remember that %28a%2Bb%29%28a-b%29=a%5E2%2Bb%5E2. Having said that, we are now going to multiply each of the fractions by 1, in the form of %288-10i%29%2F%288-10i%29:



%28%288-10i%29%288%2B10i%29%29=64-%28-100%29 (remember that i%5E2=-1), so our denominator becomes 164, giving us:

%28%288-10i%29-%288-10i%29%29%2F164

Now, to add complex numbers, you just add the real parts to the real parts and the imaginary parts to the imaginary parts: %28a%2Bbi%29%2B%28c%2Bdi%29=%28a%2Bb%29%2B%28c%2Bd%29i

In our problem, we have %28%288-8%29-%2810-10%29i%29%2F164 giving us:

0%2F164=0

If you need to express 0 in complex number (%28a%2Bbi%29) form, then you would write %280%2B0i%29.

Hope that helps.