SOLUTION: A scientist is working with two different concentrations of hydrochloric acid (HCl). Bottle C is 80% HCl, and Bottle D is 30% HCl. For their experiment they need 1 liter of 60% H

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A scientist is working with two different concentrations of hydrochloric acid (HCl). Bottle C is 80% HCl, and Bottle D is 30% HCl. For their experiment they need 1 liter of 60% H      Log On


   

Question 1208408: A scientist is working with two different concentrations of hydrochloric acid (HCl). Bottle C is 80% HCl, and Bottle D is 30% HCl. For their experiment they need 1 liter of 60% HCl. The scientist needs to know the required number of liters of each solution to use.
Write a system of equations that could be used to solve this problem.
Algebraically solve your system of equations
How many liters of Bottle C do they need?

Found 2 solutions by josgarithmetic, timofer:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Available 80% and 30%;
and want 1 liter of 60% solution;

If take c volume of the 80% then would be take 1-c of the 30%.

0.8c%2B0.3%281-c%29=1%2A0.6
highlight%280.8c%2B0.3%281-c%29=0.6%29------------solve for c, number of liters (could choose to then convert to mililiters).

Answer by timofer(105) About Me  (Show Source):
You can put this solution on YOUR website!
bottle c, 80% HCl
bottle d, 30% HCl
result to become mix to have 10 liter of 60% HCl
System of equations? This should be done in one if you see how.

The pure HCl, 0.8c%2B0.3d=1%2A0.6 but factor 1 does not give anything more.
0.8c%2B0.3d=0.6
8c%2B3d=6


Also c and d together must be 1 liter.
c%2Bd=1

Good system for you:
system%288c%2B3d=6%2Cc%2Bd=1%29

Work the rest from that.