SOLUTION: Our of 5 Bankers and 7 insurers, a committee consisting of 2 Bankers and 3 Insurers is to be formed. In how many ways can this be done if any banker and any insurer can be included

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Question 1208406: Our of 5 Bankers and 7 insurers, a committee consisting of 2 Bankers and 3 Insurers is to be formed. In how many ways can this be done if any banker and any insurer can be included?
Answer by ikleyn(52814) About Me  (Show Source):
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Our of 5 Bankers and 7 insurers, a committee consisting of 2 Bankers and 3 Insurers is to be formed.
In how many ways can this be done if any banker and any insurer can be included?
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2 bankers  from 5 bankers can be selected in  C%5B5%5D%5E2 = %285%2A4%29%2F%281%2A2%29 = 10 different ways.


3 insurers from 7 insurers can be selected in C%5B7%5D%5E3 = %287%2A6%2A5%29%2F%281%2A2%2A3%29 = 35 different ways.


The answer to the problem's question is the product

    
    C%5B5%5D%5E2%2AC%5B7%5D%5E3 = 10*35 = 350  different ways.

Solved.