SOLUTION: 4 ___ 3n + 2 ___ n+1 + 2 ___ n^2+n

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Question 120832: 4
___
3n
+
2
___
n+1
+
2
___
n^2+n
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume you mean:
4%2F%283n%29 + 2%2F%28%28n%2B1%29%29 + 2%2F%28%28n%5E2%2Bn%29%29
:
Factor out n in the 3rd denominator:
4%2F%283n%29 + 2%2F%28%28n%2B1%29%29 + 2%2F%28n%28n%2B1%29%29
:
The common denominator will be: 3n(n+1), so we have:
:
%284%28n%2B1%29+%2B+2%283n%29+%2B+3%282%29%29%2F%283n%28n%2B1%29%29 = %284n+%2B+4+%2B+6n+%2B+6%29%2F%283n%28n%2B1%29%29 = %2810n+%2B+10%29%2F%283n%28n%2B1%29%29 = %2810%28n+%2B+1%29%29%2F%283n%28n%2B1%29%29
:
The (n+1)'s cancel, we are left with:
10%2F%283n%29
:
How about this? Could you follow this ok? Any questions? Let me know.