Question 1208192: 3a+5b=3,a+2b=13
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52787)   (Show Source):
You can put this solution on YOUR website! 3a+5b=3, a+2b=13
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They want you solve this system of two equations
3a + 5b = 3, (1)
a + 2b = 13. (2)
There are different methods for it.
I will show here the SUBSTITUTION method.
From equation (2), express a = 13 - 2b.
Substitute this expression for "a" into equation (1). You will get
3*(13-2b) + 5b = 3.
It is a single equation for a single unknown "b".
Simplify it and find "b"
39 - 6b + 5b = 3,
39 - b = 3,
39 - 3 = b,
b = 36.
Substitute this value b = 36 into equation (2) and find "a"
a + 2*36 = 13,
a + 72 = 13,
a = 13 - 72 = -59.
Thus a= -59, b= 36 is the unique solution to the original system. ANSWER
You may check that each equation (1) and (2) becomes an identity, when you substitute a= -59, b= 36 there.
This check confirms that the found values are correct solutions.
Solved.
Answer by josgarithmetic(39617)  (Show Source):
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