Question 1208098: Find A, B and C,
cr[cr(2) - 1] = cr(A) + cr(B) + cr(C)
Where cr means cube root
Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website! .
One solution is obvious:
A = 0, B = 0, C = cr(2)-1.
3-1 = 2 other similar solutions can be found using permutations.
Several other solutions can be found easily.
Take A= 1, B= -1, C = cr(2)-1.
Check that it does satisfy equation.
6-1 = 5 other similar solutions can be found using permutations.
Generally speaking, there are infinitely many solutions in real numbers. A and B can be assigned by an arbitrary way,
and then value of C can be adjusted from the equation.
So, without additional restrictions, this " problem " makes a few sense.
In the form as presented, this " problem " is good as a joke
to make a reader laughing after several minutes of thinking.
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