SOLUTION: Subtract: write your answer in simplest form. y-2/y+3 subtract y/2y+6 a. y-2/y+3 b. y-4/2(y+3) c. 3y-4/2(y+3) d. y^2+y-12/(y+3)(2y+6) I do not understand how t

Algebra ->  Expressions-with-variables -> SOLUTION: Subtract: write your answer in simplest form. y-2/y+3 subtract y/2y+6 a. y-2/y+3 b. y-4/2(y+3) c. 3y-4/2(y+3) d. y^2+y-12/(y+3)(2y+6) I do not understand how t      Log On


   

Question 120809: Subtract: write your answer in simplest form.
y-2/y+3 subtract y/2y+6

a. y-2/y+3
b. y-4/2(y+3)
c. 3y-4/2(y+3)
d. y^2+y-12/(y+3)(2y+6)

I do not understand how to work the problem out to get the answer, I know the LCD is 2(y-3)(y+3). Please help me , thank you in advance.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Subtract: write your answer in simplest form.
:
y-2/y+3 subtract y/2y+6
:
%28%28y-2%29%29%2F%28%28y%2B3%29%29 - y%2F%28%282y%2B6%29%29 = %28%28y-2%29%29%2F%28%28y%2B3%29%29 - y%2F%282%28y%2B3%29%29; factored out the 2
:
The common denominator will be just: 2(y+3)
%282%28y-2%29-y%29%2F%282%28y%2B3%29%29 = %282y-4-y%29%2F%282%28y%2B3%29%29 = %28y-4%29%2F%282%28y%2B3%29%29
:
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