SOLUTION: Solve each inequality. Express your answer using set notation or interval notation. Graph the solution set. 1. |[(2x - 3)/2] + (1/3)| > 1 2. |[(2x + 3)/2] - (1/2)| < 1

Algebra ->  Inequalities -> SOLUTION: Solve each inequality. Express your answer using set notation or interval notation. Graph the solution set. 1. |[(2x - 3)/2] + (1/3)| > 1 2. |[(2x + 3)/2] - (1/2)| < 1      Log On


   



Question 1207726: Solve each inequality. Express your answer using set notation or interval notation. Graph the solution set.

1. |[(2x - 3)/2] + (1/3)| > 1

2. |[(2x + 3)/2] - (1/2)| < 1

Answer by mccravyedwin(407) About Me  (Show Source):
You can put this solution on YOUR website!
Learn how to get rid of absolute value bars || in inequalities:

abs%28EXPRESSION%29+%3C+NUMBER means -NUMBER%3CEXPRESSION%3C%22%2BNUMBER%22

Also learn that 

abs%28EXPRESSION%29+%3E+NUMBER means EXPRESSION+%3C%22-NUMBER%22matrix%281%2C2%2C%22OR%22%2C%22%22%29EXPRESSION+%3E+%22%2BNUMBER%22,

where the word "OR" is included as part of the solution.  

These apply the same whether the inequality symbol is "underlined" ("or equal to")
is implied or not.

1.  abs%28%28%282x+-+3%29%2F2%29+%2B+%281%2F3%29%29+%3E+1

That means:

%282x+-+3%29%2F2+%2B+expr%281%2F3%29+%3C+-1OR%282x+-+3%29%2F2+%2B+expr%281%2F3%29+%3E+%22%2B1%22

Multiply both inequalities through by 6

6%2A%28%282x+-+3%29%2F2+%2B+1%2F3%29+%3E+-6%2A1OR6%2A%28%282x+-+3%29%2F2+%2B+1%2F3%29+%3E+%22%2B6%22%2A1

3%282x+-+3%29+%2B+2+%3C+-6OR3%282x+-+3%29+%2B+2+%3E+6

6x+-+9+%2B+2+%3C+-6OR6x+-+9+%2B+2+%3E+6

6x+-+7+%3C+-6OR6x+-+7+%3E+6

6x+%3C+1OR6x+%3E+13

x+%3C+1%2F6ORx+%3E+13%2F6   <-- ANSWER.

---------------------------------------------------------

2. abs%28+%282x+%2B+3%29%2F2+-+%281%2F2%29+%29+%3C+1

That means:

 -1+%3C+%282x+%2B+3%29%2F2+-+%281%2F2%29+%3C+%22%2B1%22

Multiply through by 2

-2%3C+2%2A%28%282x+%2B+3%29%2F2+-+1%2F2%29+%3C+2

-2+%3C+%282x+%2B+3%29+-+1+%3C+2

-2%3C+2x+%2B+3+-+1+%3C+2

-2%3C+2x+%2B+2+%3C+2

Divide through by 2

-1%3Cx%2B1%3C1

Add -1 to all three sides:

-2%3Cx%3C0    <-- ANSWER.

Edwin