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Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set.
0 < (3x + 6)^(-1) < 1/3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Your starting inequality is
0 <
<
. (1)
Left part of this inequality, 0 <
, means that the denominator is positive
3x + 6 > 0 (otherwise,
would be negative).
It implies 3x > - 6, x >
= -2. (2)
Right part of this inequality is
<
.
Assuming that 3x+6 is positive, we can multiply both sides by 3x+6 without flipping the inequality sign.
By doing it, we get
1 <
,
or, equivalently,
1 < x+2.
It implies
x > -1. (3)
So, we have two inequalities, (2) and (3).
Therefore, the final answer is the intersection of these two sets, x > -1.
In the interval form, the solution set is (-1,infinity).
This is a graph
----|--------|--------(========|========|========|======>
-3 -2 -1 0 1 2 x
Solved.