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Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set.
0 < (3x + 6)^(-1) < 1/3
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Your starting inequality is
    0 <  <
 <  .    (1)
Left part of this inequality,  0 <
.    (1)
Left part of this inequality,  0 <  ,  means that the denominator is positive
    3x + 6 > 0    (otherwise,
,  means that the denominator is positive
    3x + 6 > 0    (otherwise,   would be negative).
It implies  3x > - 6,  x >
  would be negative).
It implies  3x > - 6,  x >  = -2.    (2)
Right part of this inequality is
 = -2.    (2)
Right part of this inequality is
     <
 <  .
Assuming that 3x+6 is positive, we can multiply both sides by 3x+6 without flipping the inequality sign.
By doing it, we get
    1 <
.
Assuming that 3x+6 is positive, we can multiply both sides by 3x+6 without flipping the inequality sign.
By doing it, we get
    1 <  ,
or, equivalently,
    1 < x+2.
It implies 
    x > -1.    (3)
So, we have two inequalities,  (2) and (3).
Therefore, the final answer is  the intersection of these two sets,  x > -1.
In the interval form, the solution set is  (-1,infinity).
This is a graph
   ----|--------|--------(========|========|========|======>
       -3       -2       -1       0        1        2     x
,
or, equivalently,
    1 < x+2.
It implies 
    x > -1.    (3)
So, we have two inequalities,  (2) and (3).
Therefore, the final answer is  the intersection of these two sets,  x > -1.
In the interval form, the solution set is  (-1,infinity).
This is a graph
   ----|--------|--------(========|========|========|======>
       -3       -2       -1       0        1        2     x
Solved.