SOLUTION: Write each expression in the form a + bi. 1. 2i(i^(-3)) 2. 2i(i^(-3)) ÷ i^(-4)

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Write each expression in the form a + bi. 1. 2i(i^(-3)) 2. 2i(i^(-3)) ÷ i^(-4)      Log On


   

Question 1207629: Write each expression in the form a + bi.
1. 2i(i^(-3))

2. 2i(i^(-3)) ÷ i^(-4)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

1.
2i%28i%5E%28-3%29%29
=2i%2Fi%5E3
=2%2Fi%5E2...........since i%5E2=-1
=2%2F-1
=-2
in the form a+%2B+bi a=-2 and b=0, so you have
-2


2. 2i%28i%5E%28-3%29%29%2Fi%5E%28-4%29....from 1. we have that 2i%28i%5E%28-3%29%29=-2
=-2%2Fi%5E%28-4%29.........i%5E%28-4%29=1%2Fi%5E4=1%2F%28i%5E2%29%5E2=1%2F%28-1%29%5E2=1
=-2%2F1
=-2