SOLUTION: 1. The rate, given that the distance is 200 feet and the time is x+3 seconds. 2. The perimeter of a rectangle, given that the length is x yards and the width is 10 yards sh

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: 1. The rate, given that the distance is 200 feet and the time is x+3 seconds. 2. The perimeter of a rectangle, given that the length is x yards and the width is 10 yards sh      Log On

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Question 120748: 1. The rate, given that the distance is 200 feet and the time is x+3 seconds.


2. The perimeter of a rectangle, given that the length is x yards and the width is 10 yards shorter.


3. gwen sold her car on consignment for x dollars. the saleswoman's commission was 10% of the selling price and Gwen received $6570.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1. The rate, given that the distance is 200 feet and the time is x+3 seconds.
Distance = RatexTime
Rate = Distance/Time
R=200%2F%28x%2B3%29

2. The perimeter of a rectangle, given that the length is x yards and the width is 10 yards shorter.
Perimeter is 2 times the length plus 2 times width.
P=2x%2B2%28x-10%29
P=4x-20
3. gwen sold her car on consignment for x dollars. the saleswoman's commission was 10% of the selling price and Gwen received $6570.
Gwen money = Selling price - Salewoman's commission
Gwen money = Selling price - 10%(Selling Price)
Gwen money = Selling price(1 - 10%)
6570=x%281-10%2F100%29
6570=x%280.90%29
x=6570%2F0.90
x=7300