SOLUTION: sin5A/sinA+cos5A/cosA=a+bcos4A

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Question 1207441: sin5A/sinA+cos5A/cosA=a+bcos4A
Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52852) About Me  (Show Source):
You can put this solution on YOUR website!
.
sin5A/sinA+cos5A/cosA=a+bcos4a
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


Without your question, this message is not a Math problem.

It is a mess of mathematical symbols, instead, without visible meaning.



Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Your problem should have been stated:
Given
sin%285A%29%2Fsin%28A%29%2Bcos%285A%29%2Fcos%28A%29%22%22=%22%22a%2Bb%2Acos%284A%29,
Determine the values of a and b.

We look up the formulas for sin(5A), cos(5A), and cos(4A)

sin%5E%22%22%285A%29%22%22=%22%2216sin%5E5%28A%29-20sin%5E3%28A%29%2B5sin%5E%22%22%28A%29

cos%5E%22%22%285A%29%22%22=%22%2216cos%5E5%28A%29-20cos%5E3%28A%29%2B5cos%5E%22%22%28A%29 

cos%5E%22%22%284A%29%22%22=%22%228cos%5E4%28A%29-8cos%5E2%28A%29%2B1

%22%22=%22%22a%2Bb%2A%288cos%5E4%28A%29-8cos%5E2%28A%29%2B1%5E%22%22%5E%22%22%29

16sin%5E4%28A%29-20sin%5E2%28A%29%2B5%2B16cos%5E4%28A%29-20cos%5E2%28A%29%2B5%22%22=%22%228b%2Acos%5E4%28A%29-8b%2Acos%5E2%28A%29%2Ba%2Bb

16sin%5E4%28A%29-20sin%5E2%28A%29%2B16cos%5E4%28A%29-20cos%5E2%28A%29%2B10%22%22=%22%228b%2Acos%5E4%28A%29-8b%2Acos%5E2%28A%29%2Ba%2Bb

We change the sines in the first two terms to cosines.  To change the first
term:

 

To change the second term

-20sin%5E2%28A%29=-20%281-cos%5E2%28A%29%5E%22%22%29=+-20%2B20cos%5E2%28A%29

Substituting:

%22%22=%22%228b%2Acos%5E4%28A%29-8b%2Acos%5E2%28A%29%2Ba%2Bb

Simplifying:

32cos%5E4%28A%29-32cos%5E2%28A%29%2B6%22%22=%22%228b%2Acos%5E4%28A%29-8b%2Acos%5E2%28A%29%2Ba%2Bb

This will be an identity if and only if the numerical coefficients on the left
are equal to the literal coefficients of corresponding like terms on the right.

system%2832=8b%2C-32=-8b%2C6=a%2Bb%29 

Either of the first two equations give b=4, substituting in the third
6=a+4 or a=2.

Answer: a=2, b=4

Edwin