SOLUTION: You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find P(Upper A and Upper A ).
Question c
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-> SOLUTION: You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find P(Upper A and Upper A ).
Question c
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Question 1207296: You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find P(Upper A and Upper A ).
Question content area bottom
Part 1
P(Upper Aand Upper A)equals=
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You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's.
You replace the first tile in the bag and then choose again. Find P(Upper A and Upper A ).
Question content area bottom
Part 1
P(Upper A and Upper A) equals =
~~~~~~~~~~~~~~~~~~
Total tiles in the bag is 3+2+4 = 9.
P(A) = = = .
Since choosing is with replacement, the conditions to choose the second tile are the same
as for the first tile.
THEREFORE, P(A and A) = P(A)*P(A) = = . ANSWER
