SOLUTION: an engineer stands at 200 feet from a tower and sights the top of the tower at a 45 degree angle of elevation. find the height of the tower.

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Question 1207281: an engineer stands at 200 feet from a tower and sights the top of the tower at a 45 degree angle of elevation. find the height of the tower.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52874) About Me  (Show Source):
You can put this solution on YOUR website!
.

You have a right-angled triangle with the angle of 45 degrees at the base - 

so, this right-angled triangle has two congruent acute angles at the base,

i.e. is isosceles right angled triangle.


Therefore, the height of the tower is 200 feet, i.e. the same length as the horizontal 
distance to the tower.

Solved.

More than obvious.



Answer by greenestamps(13208) About Me  (Show Source):
You can put this solution on YOUR website!


If the angle of elevation is 45 degrees, then the height of the tower is the same as the distance from the engineer to the tower.

ANSWER: 200 feet

If you need a formal solution....

h = height of tower

h/200 = tan(45)
h/200 = 1
h = 200